A) \[-\,152\] kJ \[mo{{l}^{-1}}\]
B) \[-\,161\]kJ \[mo{{l}^{-1}}\]
C) \[-\,322\]kJ \[mo{{l}^{-1}}\]
D) \[-\,76\]kJ \[mo{{l}^{-1}}\]
Correct Answer: C
Solution :
[c] \[\Delta {{G}^{o}}=-nF{{E}^{o}}\] Applying. \[\Delta {{G}_{1}}^{o}+\Delta {{G}_{2}}^{o}=\Delta {{G}_{3}}^{o}\] \[\Delta {{G}_{3}}^{o}=(-\,2F\times 0.44)+(-\,2F\times 1.23)\] \[\Delta {{G}_{3}}^{o}=-(2\times 96500\times 0.44+2\times 96500\times 1.23)\]\[\Delta {{G}_{3}}^{o}=-322310J\] \[\therefore \Delta {{G}_{3}}^{o}=-322KJ\]You need to login to perform this action.
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