A) + 0.255V
B) \[-\,0.255\,V\]
C) \[-\,0.254\,V\]
D) \[-\,1.055\,V\]
Correct Answer: B
Solution :
[b] \[Ag\to A{{g}^{+}}+{{e}^{-}},\]\[{{E}^{o}}=-\,0.798V\] \[{{V}^{3}}+A{{g}^{+}}+{{H}_{2}}O\to V{{O}^{2+}}+2{{H}^{+}}+Ag,\] \[{{E}^{o}}=-0.438V\] Adding, we get \[\therefore {{V}^{3+}}+{{H}_{2}}O\to V{{O}^{2+}}+2{{H}^{+}}+{{e}^{-,}}\] \[{{E}^{o}}=-0.36V\] \[{{V}^{2+}}+V{{O}^{2+}}+2{{H}^{+}}\to 2{{V}^{3+}}+{{H}_{2}}O,\] \[{{E}^{o}}=-0.614V\] Adding \[{{V}^{2+}}\to {{V}^{3+}}+{{e}^{-}}\] \[{{E}^{o}}=-0.254V\] \[{{V}^{3+}}+{{e}^{-}}\to {{V}^{2+}}\] \[{{E}^{o}}=-0.254V\]You need to login to perform this action.
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