question_answer

In acidic medium, \[MnO_{4}^{-}\] is converted to \[M{{n}^{+2}}\] when acts as an oxidizing agent. The quantity of electricity required to reduce 0.05 mol of \[MnO_{4}^{-}\] would be

A) 0.01 F  

B) 0.05 F

C) 0.25 F  

D) 0.15 F

Correct Answer: C

Solution :

[c] 1 mol \[MnO_{4}^{-}\] required = 5 mol \[{{e}^{-}}\] So 0.05 \[MnO_{4}^{-}\] required \[=5\times 0.05=0.25\] 1 mol \[{{e}^{-}}\]required \[=1F\] So 0.25 required \[=0.25\times F=0.25F\]