A) 0.01 F
B) 0.05 F
C) 0.25 F
D) 0.15 F
Correct Answer: C
Solution :
[c] 1 mol \[MnO_{4}^{-}\] required = 5 mol \[{{e}^{-}}\] So 0.05 \[MnO_{4}^{-}\] required \[=5\times 0.05=0.25\] 1 mol \[{{e}^{-}}\]required \[=1F\] So 0.25 required \[=0.25\times F=0.25F\]You need to login to perform this action.
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