JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Mock Test - Electromagnetic Induction

  • question_answer
    A metal conductor of length 1 m rotates vertically about one of its ends at an angular velocity 5 radians per second. If the horizontal component of the earth's magnetic field is\[0.2\times {{10}^{-4}}T\], then the emf developed between the two ends of the conductor is

    A) \[5\,\mu V\]       

    B) \[50\,\mu V\]

    C) \[5\,mV\]          

    D) \[50\,mV\]

    Correct Answer: B

    Solution :

    [b] \[E=\frac{1}{2}B\omega {{R}^{2}}=\frac{1}{2}\times 0.2\times {{10}^{-4}}\times 5\times 1\times 1\] \[=0.5\times {{10}^{-4}}V=54\times {{10}^{-1}}V\] \[=50\times {{10}^{-6}}V=50\mu V\]


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