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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Mock Test - Electromagnetic Induction

  • question_answer
    In an AC circuit, the voltage applied is\[E={{E}_{0}}\sin \omega t\]. The resulting current in the circuit is\[I={{I}_{0}}\sin (\omega t-\pi /2)\]. The power consumption in the circuit is given by

    A) \[P=0\] 

    B) \[P=\frac{{{E}_{0}}{{I}_{0}}}{2}\]

    C) \[P=\sqrt{2}\]\[{{E}_{0}}{{I}_{0}}\]                

    D) \[P=\frac{{{E}_{0}}{{I}_{0}}}{\sqrt{2}}\]

    Correct Answer: A

    Solution :

    [a] \[{{P}_{av}}={{E}_{V}}{{I}_{V}}\cos \phi \] Here \[\phi =\]phase difference \[=\frac{\pi }{2}\] \[\therefore {{P}_{av}}=0\]


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