A) \[0.2\,s\]
B) \[0.25\,s\]
C) \[0.25\times {{10}^{-3}}\,s\]
D) \[0.25\times {{10}^{-3}}\,s\]
Correct Answer: D
Solution :
[d] Both V and I are in the same phase. So, let us calculate the time taken by the voltage to change from peak value to rms value. Now 220\[\sin 100\pi {{t}_{1}}\] Or \[100\pi {{t}_{1}}=\frac{\pi }{2}\]or \[{{t}_{1}}=\frac{1}{200}s\] Again, \[\frac{220}{\sqrt{2}}=220\sin 100\pi {{t}_{2}}\] Or \[\frac{1}{\sqrt{2}}=\sin 100\pi {{t}_{2}}\] or \[100\pi {{t}_{2}}=\frac{3\pi }{4}\] Or \[{{t}_{2}}=\frac{3}{400}s\] Required time \[={{t}_{2}}-{{t}_{1}}=\frac{1}{400}s=2.5\times {{10}^{-3}}s\]
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