JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Mock Test - Electromagnetic Induction

  • question_answer
    A horizontal ring of radius \[r=1/2m\] is kept in a vertical constant magnetic field 1 T. The ring is collapsed from maximum area to zero area in 1 s. Then the emf induced in the ring is

    A) \[1\,V\]             

    B) \[(\pi /4)\,V\]

    C) \[(\pi /2)\,V\]      

    D) \[\pi \,V\]

    Correct Answer: B

    Solution :

    [b] \[\left| \varepsilon  \right|=B\frac{dA}{dt}\] \[\left| \varepsilon  \right|=B\frac{({{A}_{2}}-{{A}_{1}})}{({{t}_{2}}-{{t}_{1}})}\] \[\left| \varepsilon  \right|=\frac{1\left( \frac{\pi }{4}-0 \right)}{(1-0)}\] \[\varepsilon =\frac{\pi }{4}V\]


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