2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. EM Waves

JEE Main & Advanced Physics EM Waves Question Bank Mock Test - Electromagnetic Waves and Dual Nature

  • question_answer
    An electron is accelerated through a potential difference of V volt. It has a wavelength \[\lambda \] associated with it. Through what potential difference an electron must be accelerated so that its de Broglie wavelength is the same as that of a Proton? Take mass of proton to be 1837 times larger than the mass of electron.

    A) \[Vvolt\]

    B) \[1837V\,volt\]

    C) \[V/1837\,volt\]  

    D) \[\sqrt{1837}V\,volt\]

    Correct Answer: C

    Solution :

    [c] \[\lambda =\frac{h}{\sqrt{2mqV}}\,mV=\text{constant}\] \[1837V'=1\times V\]or \[V'=\frac{V}{1837}\]volt


You need to login to perform this action.
You will be redirected in 3 sec spinner