A) \[3.33\times {{10}^{18}}{{s}^{-1}},\,\,6\times {{10}^{-34}}J\text{-}s\]
B) \[6\times {{10}^{18}}{{s}^{-1}},6\times {{10}^{-34}}J\text{-}s\]
C) \[2.66\times {{10}^{18}}{{s}^{-1}},\,\,4\times {{10}^{-34}}J\text{-}s\]
D) \[4\times {{10}^{18}}{{s}^{-1}},\,\,3\times {{10}^{-34}}J\text{-}s\]
Correct Answer: A
Solution :
[a] \[{{K}_{\max }}=hv-W\] \[\omega \]is the intercept on y-axis and h is the slope. \[\therefore h=\frac{2.4\times {{10}^{-15}}}{4\times {{10}^{18}}}=6\times {{10}^{-34}}Js\] \[W=2\times {{10}^{-15}}J\] \[\Rightarrow h{{v}_{0}}=2\times {{10}^{-15}}\] Or \[{{v}_{0}}=3.33\times {{10}^{18}}s\]
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