question_answer

The potential energy of a particle of mass m is given by \[U(x)=\left\{ \begin{matrix}    {{E}_{0}};  \\    0;  \\ \end{matrix}\begin{matrix}    0\le x\le 1  \\    x>1  \\ \end{matrix} \right.\] \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] are the de Broglie wavelengths of the particle, when \[0\le x\le 1\]and \[x>1\] respectively. If the total energy of particle is 2\[{{E}_{0}}\], the ratio \[\frac{{{\lambda }_{0}}}{{{\lambda }_{2}}}\] will be

A) 2                     

B) 1         

C) \[\sqrt{2}\]        

D) \[\frac{1}{\sqrt{2}}\]