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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Mock Test - Electrostatics

  • question_answer
    The electric flux from a cube of edge \[l\] is\[\phi \]. If an edge of the cube is made \[2l\] and the charge enclosed is halved, its value will be

    A) \[4\phi \]                       

    B) \[2\phi \]

    C) \[\phi /2\]                      

    D) \[\phi \]

    Correct Answer: C

    Solution :

    [c] \[\phi =\frac{q}{{{\varepsilon }_{0}}}\] (independent of dimensions) New flux, \[\phi '=\frac{\phi }{2}\]


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