question_answer

NO and \[{{H}_{2}}S\] both the pollutants of air. NO is \[{{H}_{2}}S\] remover while \[{{H}_{2}}S\] is NO remover. Under these effect,

A) NO is oxidized to \[N{{O}_{2}}\] and \[{{H}_{2}}S\] is oxidized to \[{{H}_{2}}S{{O}_{4}}\]

B) NO is oxidized to \[N{{O}_{2}}\] and \[{{H}_{2}}S\] is reduced to \[{{H}_{2}}S{{O}_{4}}\]

C) NO is reduced to \[N{{H}_{3}}\] and \[{{H}_{2}}S\] is oxidized to sulphur

D) NO is reduced to \[{{N}_{2}}\] and \[{{H}_{2}}S\] is oxidized to sulphur

Correct Answer: D

Solution :

[d]