A) NO is oxidized to \[N{{O}_{2}}\] and \[{{H}_{2}}S\] is oxidized to \[{{H}_{2}}S{{O}_{4}}\]
B) NO is oxidized to \[N{{O}_{2}}\] and \[{{H}_{2}}S\] is reduced to \[{{H}_{2}}S{{O}_{4}}\]
C) NO is reduced to \[N{{H}_{3}}\] and \[{{H}_{2}}S\] is oxidized to sulphur
D) NO is reduced to \[{{N}_{2}}\] and \[{{H}_{2}}S\] is oxidized to sulphur
Correct Answer: D
Solution :
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