JEE Main & Advanced Physics Ray Optics Question Bank Mock Test - Geometrical Optics

  • question_answer
    The magnifying power of an astronomical telescope is 8 and the distance between the two lenses is 54 cm. The focal length of eye lens and objective lens will be respectively

    A) 6 cm and 48 cm

    B)  48 cm and 6 cm

    C) 8 cm and 64 cm

    D) 64 cm and 8 cm

    Correct Answer: A

    Solution :

    [a] \[{{f}_{0}}+{{f}_{e}}=54\] and \[\frac{{{f}_{0}}}{{{f}_{e}}}=m=8\Rightarrow {{f}_{0}}=8{{f}_{e}}\] \[\Rightarrow 8{{f}_{e}}={{f}_{e}}=54\Rightarrow {{f}_{e}}=\frac{54}{9}=6\] \[\Rightarrow {{f}_{0}}=8{{f}_{e}}=8\times 6=48\]


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