A) 15 cm
B) 12.5 cm
C) 7.5 cm
D) 10 cm
Correct Answer: B
Solution :
[b] Distance of first image \[({{I}_{1}})\]formed after refraction from the plane surface of water is \[\frac{10}{4/3}=7.5cm\] From water surface\[\left( {{d}_{app}}=\frac{{{d}_{actual}}}{\mu } \right)\]. Now, distance of this image is 5+7.5=12.5 cm from the plane mirror, therefore distance of second image \[5+7.5=12.5cm\]\[({{I}_{2}})\]will also be equal to 12.5 cm from the mirror.
You need to login to perform this action.
You will be redirected in
3 sec
