A) \[{{\left[ \frac{2KGM}{g} \right]}^{1/2}}-\frac{1}{2}K'R\]
B) \[{{\left[ \frac{KGM}{2g} \right]}^{1/2}}-\frac{1}{2}K'R\]
C) \[{{\left[ \frac{KGM}{g} \right]}^{1/2}}-\frac{1}{2}K'R\]
D) \[{{\left[ \frac{KGM}{g} \right]}^{1/2}}-K'R\]
Correct Answer: D
Solution :
[d] we will be thrown into space, if weight mg is equal to gravitational force duet to the planet. If y is the closest distance. \[\frac{GMm}{{{R}^{2}}}=mg=\frac{G(KM)m}{{{(K'R+y)}^{2}}}\] \[{{(K'R+y)}^{2}}=\frac{KGM}{g}\] \[y={{\left( \frac{KGM}{g} \right)}^{1/2}}-K'R\]You need to login to perform this action.
You will be redirected in
3 sec