A) \[\frac{1}{103}\]
B) \[\frac{1}{206}\]
C) \[\frac{2}{309}\]
D) \[\frac{1}{412}\]
Correct Answer: D
Solution :
[d] 1g of \[{{C}_{8}}{{H}_{7}}S{{O}_{3}}Na=\frac{1}{206}mol\] \[2{{C}_{8}}{{H}_{7}}S{{O}_{3}}NA+C{{a}^{2+}}\to {{({{C}_{8}}{{H}_{7}}S{{O}_{3}})}_{2}}Ca+2N{{a}^{+}}\] 2 mol of resin requires 1 mol \[2\times 206g\]Of resin requires 1 mol 1 g of resin requires \[\frac{1}{412}\] mol
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