A) hydrogen is liberated at the cathode
B) hydrogen is liberated at anode
C) hydride ion migrates towards cathode
D) no reaction takes place
Correct Answer: B
Solution :
[b] \[{{M}^{+}}{{H}^{-}}\to {{M}^{+}}+\underset{hydride\,ion}{\mathop{{{H}^{-}}}}\,\] \[{{H}^{-}}\to \frac{1}{2}{{H}_{2}}+{{e}^{-}}\] (At anode)
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