A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
[b] \[{{\sin }^{-1}}\left| x-2 \right|+{{\cos }^{-1}}(1-\left| 3-x \right|)=\frac{\pi }{2}\] Or \[\left| x-2 \right|=1-\left| 3-x \right|\] Or \[\left| x-2 \right|+\left| 3-x \right|=\left| (x-2)+(3-x) \right|\] Or \[(x-2)(3-x)\ge 0\] Or \[2\le x\le 3\]You need to login to perform this action.
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