A) \[3\sqrt{3:}8\]
B) \[16:9\sqrt{3}\]
C) \[4:9\]
D) \[2\sqrt{2}:3\]
Correct Answer: B
Solution :
[b] \[T=2\pi \sqrt{\frac{I}{MB\cos \delta }}\] \[v=\frac{1}{2\pi }\sqrt{\frac{MB\cos \delta }{I}}\] \[v=\sqrt{B\cos \delta }\] or \[B\propto \frac{{{v}^{2}}}{\cos \delta }\] \[\frac{{{B}_{1}}}{{{B}_{2}}}=\frac{400}{\cos 30{}^\circ }\times \frac{\cos 60{}^\circ }{225}=\frac{16\times 2}{9\times \sqrt{3}}\times \frac{1}{2}=16:9\sqrt{3}\]
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