JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Mock Test - Magnetics

  • question_answer
    An electron is launched with velocity \[\vec{v}\] in a uniform magnetic field\[\vec{B}\]. The angle \[\theta \] between \[\vec{v}\] and \[\vec{B}\] lies between 0 and\[\pi /2\]. Its velocity vector \[\vec{v}\] returns to its initial value in a time interval of

    A) \[\frac{2\pi m}{eB}\]     

    B) \[\frac{2\times 2\pi m}{eB}\]

    C) \[\frac{\pi m}{eB}\]       

    D) Depends upon angle between \[\vec{v}\] and \[\vec{B}\]

    Correct Answer: A

    Solution :

    [a] Time interval in which \[\vec{v}\]returns to its initial value is same as time period of the particle, hence the required time \[=\frac{2\pi m}{eB}\]


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