A) \[ilb\]
B) \[2ilb\]
C) \[3\,ilb\]
D) Zero
Correct Answer: A
Solution :
[a] The equivalent figure can be redrawn as shown in figure. Force on \[AB=ilB\], force on \[BCA=2ilB\] in opposite direction to that on \[BA.\] Hence, net force\[=2ilB-ilB=ilB\]
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