A) \[{{30}^{0}}\]
B) \[{{45}^{0}}\]
C) \[{{60}^{0}}\]
D) \[{{90}^{0}}\]
Correct Answer: B
Solution :
[b] Torque of magnetic force about PQ \[{{\tau }_{m}}=(ILB)Lcos\theta =I{{L}^{2}}B\cos \theta \] Torque of gravitational force about PQ \[{{\tau }_{g}}=[(\lambda L)gLsin\theta +2(\lambda L)g(1/2)Lsin\theta ]\lambda {{L}^{2}}g\sin \theta \]\[{{\tau }_{m}}={{\tau }_{g}}\Rightarrow \tan \theta =\frac{IB}{2\lambda g}=\frac{10\sqrt{3}\times 2}{2\times \sqrt{3}\times 10}=1\] \[\Rightarrow \theta =45{}^\circ \]
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