A) \[\frac{\pi }{2}BIl\]
B) \[\frac{BIl}{2}\]
C) \[\frac{BIl}{2\pi }\]
D) \[BIl\]
Correct Answer: C
Solution :
[c] \[BI\,(dl)=2T\sin (d\theta /2)\] \[\Rightarrow BI(rd\theta )=2T(d\theta \text{/}2)\] (\[\theta \]is small, \[(\sin \theta =\theta )\] \[\Rightarrow T=BIr=BIl/2\pi \]You need to login to perform this action.
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