A) contradiction
B) tautology
C) neither [a] nor [b]
D) none of the above
Correct Answer: B
Solution :
[b]\[p\Rightarrow q\] | \[\sim p\Rightarrow \sim q\] | \[p\Rightarrow q\Leftrightarrow \sim q\Rightarrow \sim p\] |
T | T | T |
F | F | T |
T | T | T |
T | T | T |
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