A) equivalent to \[p\leftrightarrow q\]
B) equivalent to ~\[p\leftrightarrow q\]
C) a tautology
D) a fallacy
Correct Answer: A
Solution :
[a]p | q | \[\sim q\] | \[p\leftrightarrow \sim q\] | \[\sim (p\leftrightarrow \sim q)\] | \[p\leftrightarrow q\] |
T | T | F | F | T | T |
T | F | T | T | F | F |
F | T | F | T | F | F |
F | F | T | F | T | T |
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