A) 0.1
B) 0.05
C) 0.005
D) 0.0005
Correct Answer: D
Solution :
[d] \[A={{(0.1)}^{2}}=0.01{{m}^{2}},\eta =0.01\]poise = 0.001 decapoise (M.K.S. unit), \[dv=0.1\text{ }m/s\] and \[F=0.002\text{ }N\] \[F=\eta A\frac{dv}{dx}\] \[\therefore dx=\frac{\eta Adv}{F}=\frac{0.001\times 0.01\times 0.1}{0.002}=0.0005m\]
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