A) \[x+y\]
B) \[x-y\]
C) \[\frac{x+y}{r}\]
D) \[\frac{x-y}{r}\]
Correct Answer: D
Solution :
[d] \[{{v}_{0}}=\frac{2}{9}\frac{{{r}^{2}}(\rho -\rho ')g}{\eta }\] \[Now,\text{ }x=\frac{4}{3}\pi {{r}^{3}}\rho \,\,or\text{ }\rho \propto \frac{x}{{{r}^{3}}}\] \[Similarly,\text{ }\rho '\propto \frac{y}{{{r}^{3}}}\] \[\therefore {{v}_{0}}\propto \frac{x-y}{r}\]
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