A) \[h\]
B) \[h/2\]
C) \[h/4\]
D) \[h4\]
Correct Answer: B
Solution :
[b] \[h=\frac{2S\cos \theta }{rpg}\] Cross-sectional area increases four times, which means radius get doubles. So \[h'=\frac{2S}{2(rpg)}=\frac{h}{2}\]You need to login to perform this action.
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