A) \[\frac{3}{2}cm\]
B) \[\sqrt{6}cm\]
C) \[\sqrt{3}cm\]
D) \[3cm\]
Correct Answer: D
Solution :
[d] \[x=\sqrt{2g{{h}_{1}}}\times \sqrt{\frac{2{{h}_{2}}}{g}}\]or \[x=2\sqrt{{{h}_{1}}{{h}_{2}}}\] Now imagine a hole at a depth \[{{h}_{2}}\]below the free surface of the liquid. The height of this hole will be \[{{h}_{1}}\]clearly, x remains the same.
You need to login to perform this action.
You will be redirected in
3 sec
