A) \[1\,MeV\]
B) \[11.9\,MeV\]
C) \[23.8\,MeV\]
D) \[931\,MeV\]
Correct Answer: C
Solution :
[c] Mass of \[_{1}{{H}^{2}}\]= 2.01478 a.m.u. Mass of \[_{2}{{H}^{4}}\]= 4.00388 a.m.u. Mass of two deuterium \[=2\times 2.01478=4.02956\] Energy equivalent to \[{{2}_{1}}{{H}^{2}}\] \[=4.02956\times 1.112\] MeV \[=4.48\]MeV Energy equivalent to \[_{2}{{H}^{4}}\] \[=7.00388\times 7.047\]MeV\[=28.21MeV\] Energy released \[=28.21-4.48\] \[=23.73\]MeV\[=24\]MeVYou need to login to perform this action.
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