JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Mock Test - Modern Physics

  • question_answer
    The wavelength of radiation emitted is \[{{\lambda }_{0}}\] when an electron jumps from the third to the second orbit of hydrogen atom. For the electron jump from the fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be\[K{{\lambda }_{0}}\]. Find the value of K.

    Answer:

    \[\left( \frac{20}{27} \right)\]


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