A) \[\sqrt{2T}\]
B) \[\frac{T}{2}\]
C) \[T\]
D) \[2T\]
Correct Answer: B
Solution :
[b] with respect to lift initial speed = \[{{v}_{0}}\] Acceleration = -2g Displacement = 0\[\therefore S=ut+\frac{1}{2}a{{t}^{2}}\] \[0={{v}_{0}}T'+\frac{1}{2}\times 2g\times T{{'}^{2}}\] \[\therefore T'=\frac{{{v}_{0}}}{g}=\frac{1}{2}\times \frac{2{{v}_{0}}}{g}=\frac{1}{2T}\]
You need to login to perform this action.
You will be redirected in
3 sec
