JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Mock Test - Motion in one Dimension

  • question_answer
    A frictionless wire AB is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is

    A) \[\frac{2\sqrt{gR}}{g\cos \theta }\]          

    B) \[2\sqrt[{}]{gR,}\]\[\frac{\cos \theta }{2}\]

    C) \[\sqrt[2]{\frac{R}{g}}\]             

    D) \[\frac{gR}{\sqrt{g\cos \theta }}\]

    Correct Answer: C

    Solution :

    [c] Acceleration of body along AB is Distance travelled in time t sec=AB=\[\frac{1}{2}\]\[(gcos\theta ){{t}^{2}}\] From \[\Delta ABC\], AB =\[2R\cos \theta ;2R\cos \theta =\frac{1}{2}g\cos \theta {{t}^{2}}\] \[\Rightarrow {{t}^{2}}=\frac{4R}{8}\]or \[t=2\sqrt{\frac{R}{g}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner