A) \[{{v}^{2}}\le \alpha x\]
B) \[{{v}^{2}}\le 2\alpha x\]
C) \[{{v}^{2}}\ge 2\alpha x\]
D) \[{{v}^{2}}\ge \alpha x\]
Correct Answer: C
Solution :
[c] If police is able to catch the dacoit after time t, then \[Vt=x+\frac{1}{2}a{{t}^{2}}\]. This gives \[\frac{a}{2}{{t}^{2}}-vt+x=0\] Or \[t=\frac{v\pm \sqrt{{{v}^{2}}-2\alpha x}}{\alpha }\] For t to be real, \[{{v}^{2}}\ge 2ax\]
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