A) \[{{\sin }^{-1}}\left( \frac{1}{8} \right)\]
B) \[\frac{1}{2}{{\sin }^{-1}}\left( \frac{1}{8} \right)\]
C) \[\frac{1}{3}{{\sin }^{-1}}\left( \frac{1}{8} \right)\]
D) \[\frac{1}{4}{{\sin }^{-1}}\left( \frac{1}{8} \right)\]
Correct Answer: B
Solution :
[b] \[\frac{{{u}^{2}}\sin 2\theta }{g}=\frac{{{(u/2)}^{2}}\sin 30{}^\circ }{g}=\frac{{{u}^{2}}}{8g}\] \[\therefore \sin 2\theta =\frac{1}{2}\]or \[\theta =\frac{1}{2}{{\sin }^{-1}}\left( \frac{1}{8} \right)\]You need to login to perform this action.
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