A) \[\frac{2\ell }{\sqrt{{{V}^{2}}-{{v}^{2}}}}\]
B) \[\frac{2v\ell }{{{V}^{2}}-{{v}^{2}}}\]
C) \[\frac{2V\ell }{{{V}^{2}}-{{v}^{2}}}\]
D) \[\frac{2\ell }{\sqrt{{{V}^{2}}+{{v}^{2}}}}\]
Correct Answer: A
Solution :
[a] For no drift: \[V\sin \theta =v\] \[\sin \theta =\frac{v}{V}\] \[\therefore t={{t}_{AB}}+{{t}_{BA}}\] \[t=\frac{2\ell }{V\cos \theta }=\frac{2\ell }{V\sqrt{1-\frac{{{v}^{2}}}{{{V}^{2}}}}}\Rightarrow t=\frac{2\ell }{\sqrt{{{V}^{2}}-{{v}^{2}}}}\]You need to login to perform this action.
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