A) \[\left( \frac{3}{2\mu } \right)mg\]
B) \[\left( \frac{5}{2\mu } \right)mg\]
C) \[\left( \frac{5}{2} \right)\mu mg\]
D) \[\left( \frac{3}{2} \right)\mu mg\]
Correct Answer: B
Solution :
[b] Horizontal acceleration of the system is \[a=\frac{F}{2m+m+2m}=\frac{F}{5m}\] Let N be the normal reaction between B and C. Free body diagram of C gives \[N=2ma=\frac{2}{5}F\] Now B will not slide downward if \[\mu N\ge {{m}_{B}}g\] Or \[\mu \left( \frac{2}{5}F \right)\ge mgorF\ge \frac{5}{2\mu }mg\] \[{{F}_{\min }}=\frac{5}{2\mu }mg\]You need to login to perform this action.
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