A) \[5\,N\]
B) \[\frac{20}{2+\sqrt{3}}N\]
C) \[\frac{20}{2-\sqrt{3}}N\]
D) \[10\,N\]
Correct Answer: B
Solution :
[b] \[R+F\sin 60{}^\circ =mg\] \[R=mg-\frac{\sqrt{3}F}{2}\] If block just starts moving \[F\cos 60{}^\circ =f=\mu R\] Or \[F+\frac{\sqrt{3}F}{2}=10\]or \[F=\frac{20}{2+\sqrt{3}}\]You need to login to perform this action.
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