A) \[30{}^\circ \]
B) \[{{\tan }^{-1}}(2\sqrt[{}]{3})\]
C) \[{{\tan }^{-1}}(\sqrt[{}]{3}/2)\]
D) \[{{\tan }^{-1}}(2)\]
Correct Answer: B
Solution :
[b] \[T\sin \theta -mg\sin 30{}^\circ =ma\] \[\Rightarrow T\sin \theta =mg\sin 30{}^\circ +mg/2(i)\] \[T\cos \theta =mg\cos 30{}^\circ (ii)\] Dividing Eqs. (i) by (ii), we get \[\tan \theta =\frac{2}{\sqrt{3}}\]You need to login to perform this action.
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