A) \[F\]
B) \[2\,F/3\]
C) \[3\,F/5\]
D) \[5\,F/6\]
Correct Answer: D
Solution :
[d] The acceleration of block-rope system is \[a=\frac{F}{(M+m)}\] Where M is the mass of block and m is the mass of rope. So the tension in the middle of the rope will be \[T=\{M+(m/2)\}a=\frac{M+(m/2)F}{M+m}\] Given that m=M/2 \[\therefore T=\left[ \frac{M+(M/4)}{M+(M/2)} \right]F=\frac{5F}{6}\]You need to login to perform this action.
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