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JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques / कार्बनिक रसायन : कुछ मूलभूत सिद्धांत एवं तकन Question Bank Mock Test - Organic Chemistry : Some Basic Principles and Techniques

  • question_answer
    An organic compound of analysis gave c = 48 g H = 8 g and N = 56 g. Volume of 1.0 g of the compound was found to be 200 ml at NTP. Molecular formula of the compound is

    A) \[{{C}_{4}}{{H}_{8}}{{N}_{4}}\]     

    B) \[{{C}_{2}}{{H}_{4}}{{N}_{2}}\]

    C) \[{{C}_{12}}{{H}_{24}}{{N}_{12}}\]

    D) \[{{C}_{16}}{{H}_{32}}{{N}_{16}}\]

    Correct Answer: A

    Solution :

    [a]
    Element % no. of moles simple ratio
    C 48 48/12=4 1
    H 8 8/1=8 2
    N 56 56/14=4 1
    Empirical formula\[=C{{H}_{2}}N\] Empirical formula mass\[=28\] Now. 200ml of compound\[=1\,g\] 22400 ml of compound \[\frac{1}{200}\times 22400=12\] \[n=\frac{Mol.mass}{Emp\,formula\,mass}=\frac{112}{28}=4\] Therefore, molecular formula \[={{(C{{H}_{2}}N)}_{4}}={{C}_{4}}{{H}_{8}}{{N}_{4.}}\]


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