A)
B)
C)
D)
Correct Answer: B
Solution :
[b] \[S{{H}^{-}}>O{{H}^{-}}\to \] down the group size of S > 0 \[\therefore \]nucleophilicity \[S{{H}^{-}}>O{{H}^{-}}\] as nucleophilicity \[\propto \frac{1}{size}\] \[O{{H}^{-}}>Ph{{O}^{-}}\to Ph\] is EWG \[Ph{{O}^{-}}>Ac{{O}^{-}}\to \]Because of presence of carbonyl in \[Ac{{O}^{-}}\]there is delocalization of -ve charge \[{{H}_{2}}O\to \]Being neutral it is least nucleophilic.
You need to login to perform this action.
You will be redirected in
3 sec
