JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Mock Test - Permutations and Combinations

  • question_answer
    The number of ways to give 16 different things to three persons A,B,C so that B gets one more than A and C gets two more than B is

    A) \[\frac{16!}{4!5!7!}\]    

    B) \[4!5!7!\]

    C) \[\frac{16!}{3!5!8!}\]    

    D) none of these

    Correct Answer: A

    Solution :

    [a] Obviously, A, B, and C get 4, 5, and 7 objects, respectively. Then number of distribution ways is equal to number of division of ways, which is given by 16!(4!5!7!).

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