JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Mock Test - Permutations and Combinations

  • question_answer
    The number of ways to give 16 different things to three persons A,B,C so that B gets one more than A and C gets two more than B is

    A) \[\frac{16!}{4!5!7!}\]    

    B) \[4!5!7!\]

    C) \[\frac{16!}{3!5!8!}\]    

    D) none of these

    Correct Answer: A

    Solution :

    [a] Obviously, A, B, and C get 4, 5, and 7 objects, respectively. Then number of distribution ways is equal to number of division of ways, which is given by 16!(4!5!7!).


You need to login to perform this action.
You will be redirected in 3 sec spinner