A) 240
B) 420
C) 720
D) none of these
Correct Answer: B
Solution :
[b] We first select 2 man out on 7 in \[^{7}{{C}_{2}}\]ways. Now we exclude the wives of these two selected men and so select 2 ladies form remaining 5 ladies in \[^{5}{{C}_{2}}\]ways. Let A, B be two men and X, Y be the ladies playing in one set. Then we can have (i) A and X plying against B and Y. (ii) A and Y playing against B and X. Then the total number of ways is \[^{7}{{C}_{2}}{{\times }^{5}}{{C}_{2}}\times 2=21\times 10\times 2=420\].
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