A) \[2{{f}_{2n}}(1)\]
B) \[{{f}^{2}}_{n}(1)\]
C) \[{{f}_{2n}}(1)\]
D) \[-{{f}_{2n}}(4)\]
Correct Answer: B
Solution :
[b] \[{{f}_{n}}(3)=333...3\](n digits) and \[{{f}_{n}}^{2}(3)=999...9\](n digits), \[{{f}_{n}}(2)=222...2\](n digits) |
\[\therefore \] \[{{f}_{n}}^{2}(3)+{{f}_{n}}(2)=12...2221((n+1)digits)\] |
Answer cannot be (1), (3) or (4) |
\[{{f}_{n}}(1)=111...1\](n digits) |
\[\therefore \] \[{{f}_{n}}^{2}(3)(1)=122...21((n+1)digits).\] |
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