A) \[X=C{{O}_{2}}\], \[Y=C{{l}_{2}}\]
B) \[X=C{{l}_{2}}\], \[Y=C{{O}_{2}}\]
C) \[X=C{{l}_{2}}\], \[Y={{H}_{2}}\]
D) \[X={{H}_{2}}\], \[Y=C{{l}_{2}}\]
Correct Answer: C
Solution :
[c] \[\underset{(X)}{\mathop{C{{l}_{2}}}}\,+{{H}_{2}}O\to HOCl+HCl\] \[AgN{{O}_{3}}+HCl\to \underset{white\,ppt}{\mathop{AgCl}}\,+HN{{O}_{3}}\] \[Mg+2HCl\to MgC{{l}_{2}}+\underset{(Y)}{\mathop{{{H}_{2}}}}\,\uparrow \]You need to login to perform this action.
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