A) 4/27
B) 5/38
C) 1/8
D) 9/80
Correct Answer: B
Solution :
[b] Consider the following events: A: getting a card with mark I in first draw B: getting a card with mark I in second draw C: getting a card with mark T in this draw Then, the required probability is \[P(A\cap B\cap C)=P(A)P(B/A)P(C/A\cap B)\] \[=\frac{10}{20}\times \frac{9}{19}\times \frac{10}{18}=\frac{5}{38}\]You need to login to perform this action.
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