A) 1/4
B) 1/3
C) 1/12
D) 1/10
Correct Answer: A
Solution :
[a] \[n(S)={}^{10}{{C}_{7}}=120\] \[n(A)={}^{5}{{C}_{4}}\times {}^{3}{{C}_{2}}\times {}^{2}{{C}_{1}}\] \[P(E)=\frac{5\times 3\times 2}{120}=\frac{1}{4}\]You need to login to perform this action.
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